Resposta :

ArthurPDC
[tex]\dfrac{(x-y)^{2}-2(x-y)}{ax-ay+2x-2y}=\dfrac{(x-y)[(x-y)-2]}{a(x-y)+2(x-y)}=\dfrac{(x-y)[(x-y)-2]}{(x-y)(a+2)}\\\\=\dfrac{x-y-2}{a+2}[/tex]

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