Resposta :

[tex]y=\frac{\ln c}{x}\\\\y'=\frac{(\ln c)'\cdot x-\ln c \cdotx'}{x^2}\\\\y'=\frac{0\cdot x-\ln c \cdot1}{x^2}\\\\\boxed{y'=-\frac{\ln c}{x^2}}[/tex]

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