Resposta :
[tex]Ola\ Ange\\ Usaremos \ a\ formula\ da\ tg\ da\ soma\\ \\ Tg(X+Y)= \frac{tgX+tgY}{1-tgX . tgY} \ \ trocando\ tg(x+y) =33\ e\ tgx = 3\\ \\ 33 = \frac{3+tgY}{1-3tgY} \\ \\ 33(1-3tgY) = 3+tgY \\ \\ 33 - 99tgY = 3 + tgY \\ \\ 33 - 3 = 99tgY+ tgY \\ \\ 30 = 100tgY \\ \\ \frac{30}{100} = tgY \\ \\ 0,3 = tgY \\ \\ [/tex]